High School

Jayne is taking two AP classes and three regular classes. Her AP classes count twice as much as her regular classes in her GPA. Each A is worth 4 points, Bs are worth 3 points, Cs are worth 2 points, and Ds are worth 1 point. What is Jayne's GPA?

Class Grades:
- AP English: C
- AP Government: B
- Algebra II: B
- Spanish: D
- Physics: A

Answer :

Jayne's GPA is 3.6.

To solve, add the number of grade points for each letter grade and divide by the total number of letter grades.

AP English ⇒ 4 points
AP Government ⇒ 6 points
Algebra II ⇒ 3 points
Spanish ⇒ 1 point
Physics ⇒ 4 points
4 + 6 + 3 + 1 + 4 = 18
18 / 5 = 3.6

Jayne's GPA is approximately 2.57.

For AP classes, we'll multiply by two since they count twice as much in the GPA calculation. Then we sum up all the points and divide by the total number of classes, taking the weights into account. Here's how Jayne's grades translate into points:

  • AP English (C) = 2 points
  • AP Government (B) = 3 points
  • Algebra II (B) = 3 points
  • Spanish (D) = 1 point
  • Physics (A) = 4 points

For the AP classes:

  • AP English = 2 points x 2 (weight) = 4 total points
  • AP Government = 3 points x 2 (weight) = 6 total points

For the regular classes:

  • Algebra II = 3 points
  • Spanish = 1 point
  • Physics = 4 points

Now, we'll add all the points up:

  1. AP points = 4 (English) + 6 (Government) = 10 points
  2. Regular class points = 3 (Algebra II) + 1 (Spanish) + 4 (Physics) = 8 points
  3. Total points = AP points + Regular class points = 10 points + 8 points = 18 points

The total number of 'weighted' classes is 2 (AP classes) x 2 (weight) + 3 (regular classes) = 7.

Finally, we'll calculate the GPA:

GPA = Total points / Total number of 'weighted' classes = 18 points / 7 = approximately 2.57

So, Jayne's GPA would be approximately 2.57.

Other Questions