Jack has a mass of 42 kg and jumps from a window 9 m above the ground. If he lands on the trampoline with a constant of 215 N/m, how far will the trampoline stretch?

2) Becky has a mass of 60 kg and jumps from a window 10 m above the ground. If she lands on the trampoline with a constant of 195 N/m, how fast will he be moving just prior to hitting the trampoline?

To calculate the stretch of the trampoline when Jack lands on it, we can use Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

First, let's calculate the force exerted by Jack on the trampoline. The force can be calculated using the formula:

Force = Spring Constant * Displacement

Given that the spring constant of the trampoline is 215 N/m and Jack's mass is 42 kg, we can calculate the force:

Force = 215 N/m * 9 m = 1935 N

Now, we can use Hooke's Law to calculate the stretch of the trampoline. Hooke's Law can be rearranged as:

Displacement = Force / Spring Constant

Substituting the values, we get:

Displacement = 1935 N / 215 N/m = 9 m

Therefore, the trampoline will stretch by 9 meters when Jack lands on it.

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