Answer :
a) The lowest order Feynman diagram for elastic electromagnetic electron-proton scattering (e+pe+p) involves the exchange of a virtual photon between the electron and proton. The diagram consists of an incoming electron, an incoming proton, an outgoing electron, and an outgoing proton, with a photon exchanged between the electron and proton lines.
b) The corresponding Matrix element for elastic electromagnetic electron-proton scattering can be calculated using quantum electrodynamics (QED) formalism. It involves evaluating the matrix element of the interaction Hamiltonian between the initial and final states of the electron and proton. The specific mathematical expression for the matrix element depends on the specific form of the interaction Hamiltonian used in the calculation.
c) To show that the cross-section (σ) is proportional to [tex]\frac{1}{\sin\left(\frac{\theta}{2}\right)}[/tex], where θ is the scattering angle, a detailed analysis of the scattering process and the corresponding differential cross-section formula is required. By considering the conservation of energy and momentum and applying the principles of quantum field theory, the scattering amplitude can be derived, and from there, the differential cross-section can be calculated. The resulting expression will involve factors related to the scattering angle, and by analyzing it, we can demonstrate the relationship between the cross-section and [tex]\frac{1}{\sin\left(\frac{\theta}{2}\right)}[/tex].
To learn more about Electromagnetic
brainly.com/question/31038220
#SPJ11
The complete question is:
(6) In this elastic electromagnetic ep scattering: e+pe+p a. Draw the lowest order Feynman diagram b. Find the corresponding Matrix element c. Show that σ α. 1 sin
