High School

In the laboratory, a student finds that it takes 94.8 Joules to increase the temperature of 10.7 grams of solid titanium from 20.6 to 38.8 degrees Celsius. What is the specific heat of titanium calculated from her data?

Answer :

Final answer:

To find the specific heat of the titanium, you use the formula for specific heat capacity: c = q / (m * ∆T). Given the conditions in the problem, the specific heat capacity of titanium is calculated to be 0.487 J/g°C.

Explanation:

The specific heat capacity of a substance can be calculated using the formula:
c = q / (m * ∆T),
where 'c' is the specific heat capacity, 'q' is the heat energy absorbed or released, 'm' is the mass of the substance, and '∆T' is the change in temperature.

Given:
q = 94.8 J, m = 10.7 g, ∆T = (38.8-20.6)°C = 18.2°C.

Substituting these values into the formula gives:
c = 94.8 J / (10.7 g * 18.2°C) = 0.487 J/g°C.

So, the specific heat capacity of titanium is 0.487 J/g°C.

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