High School

In the laboratory a student finds that it takes 40.9 Joules to increase the temperature of 12.1 grams of solid silver from 23.1 to 38.6 degrees Celsius. The specific heat of silver calculated from her data is .... J/g°C.

Answer :

The specific heat of silver calculated from the given data is approximately 0.223 J/g°C.

To calculate the specific heat of silver (c), we can use the formula:

q = m * c * ∆T

where q is the heat absorbed or released, m is the mass of the substance, c is the specific heat, and ∆T is the change in temperature.

q = 40.9 J

m = 12.1 g

∆T = 38.6°C - 23.1°C = 15.5°C

Rearranging the formula, we can solve for c:

c = q / (m * ∆T)

Substituting the given values:

c = 40.9 J / (12.1 g * 15.5°C)

c ≈ 0.223 J/g°C

To know more about specific heat refer to-

https://brainly.com/question/31608647

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