Answer :
After calculations, we found that the specific heat of lead calculated from the given data is 0.113 J/g∘C.
To calculate the specific heat of lead (J/g∘C) using the given data, we can use the formula:
q = m * c * ΔT
q is the heat energy absorbed by the lead (29.7 J),
m is the mass of the lead (13.2 g),
c is the specific heat of lead (unknown), and
ΔT is the change in temperature (38.8 - 23.4 = 15.4 ∘C).
Substituting the known values into the equation, we have:
29.7 J = 13.2 g * c * 15.4 ∘C
Simplifying the equation, we can isolate c:
c = 29.7 J / (13.2 g * 15.4 ∘C)
c ≈ 0.113 J/g∘C
Therefore, the specific heat of lead calculated from the given data is approximately 0.113 J/g∘C.
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