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------------------------------------------------ In the example of 100 ME students, suppose we only sampled 20 ME students and found the sample mean to be 145 lb and the sample standard deviation to be 30 lb. What would be the "t" value if we want to identify the single-sided 95% confidence interval?

Answer :

Final answer:

The 't' value can be calculated by dividing the sample mean by the standard error. In this case, the value would be approximately 21.6.

Explanation:

The 't' value is calculated from the sample mean, sample standard deviation, and sample size. First, to find the standard error of the mean, which is the standard deviation divided by the square root of the sample size, we have 30lb / sqrt(20) = about 6.71 lb.

Then, to find the single-sided 95% confidence interval, we would use a t-distribution table for a 95% confidence interval with 19 degrees of freedom (20 students - 1). The value in such a table would be approximately 1.729.

So, the t value would be sample mean (145 lb) divided by the standard error(6.71 lb), which is approximately 21.6.

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