In House 1, the mice have a frequency of the "curly coat allele" of 0.7. In House 2, the frequency of that allele is 0.4. Each house contains a population of 40 mice. There are regularly 5 migrants from each house to the other every generation.

- What is m for House 1?
- What will the expected frequency of the curly coat allele be in the next generation of House 2? Show your work to the nearest 0.01.
- Is evolution occurring in these populations? How do you know?

A) m for House 1 is 0.025; The expected frequency of the curly coat allele in the next generation of House 2 is 0.42; Yes, evolution is occurring as allele frequencies are changing.

B) m for House 1 is 0.05; The expected frequency of the curly coat allele in the next generation of House 2 is 0.44; No, evolution is not occurring.

C) m for House 1 is 0.025; The expected frequency of the curly coat allele in the next generation of House 2 is 0.4; No, evolution is not occurring.

D) m for House 1 is 0.05; The expected frequency of the curly coat allele in the next generation of House 2 is 0.42; Yes, evolution is occurring as allele frequencies are changing.

m for House 1 is 0.125; The expected frequency of the curly coat allele in the next generation of House 2 is 0.42; Yes, evolution is occurring as allele frequencies are changing.

Explanation:

In order to calculate m for House 1, we need to divide the number of migrants by the total population. Since there are 5 migrants from each house and a total population of 40 mice, m for House 1 is 5/40 = 0.125. To calculate the expected frequency of the curly coat allele in the next generation of House 2, we use the formula:

Expected frequency = initial frequency + (1-migration rate) * (frequency of migrants)

Plugging in the values, we get:

Expected frequency = 0.4 + (1-0.05) * (0.7) = 0.42

Evolution is occurring in these populations because the allele frequencies are changing due to migration of mice between the houses.

Learn more about Evolution here:

https://brainly.com/question/13492988

#SPJ11