High School

In Drosophila, wild type (V) is dominant to vestigial (v) wings, and brown (Y) is dominant to yellow (y) bodies. The genes controlling these traits are linked.

Flies that are true breeding for wild type wings and brown bodies were crossed with flies that are true breeding for vestigial wings and yellow bodies. The F1 generation was test-crossed, and the following offspring were observed:

- 356 wild type wings, brown bodies
- 8 wild type wings, yellow bodies
- 10 vestigial wings, brown bodies
- 326 vestigial wings, yellow bodies

Based on this data, what is the genetic distance between these two genes?

Options:
A. 18
B. 1.8
C. 97.3
D. 2.6

Answer :

The genetic distance between the two genes can be determined by using recombination frequency. The recombination frequency is 2.6 (Option D).

Recombination frequency can be calculated by the formula below:

Recombination frequency = (Number of recombinant progeny / Total number of progeny) × 100

Therefore, to calculate the genetic distance between these two genes, we need to determine the number of recombinant progeny and the total number of progeny.

In this scenario, wild type (v) is dominant to vestigial (v) wings, and brown (y) is dominant to yellow (y) bodies. The genes controlling these traits are linked. Flies that are true breeding for wild-type wings and brown bodies were crossed with flies that are true breeding for vestigial wings and yellow bodies.

The f1s were test crossed and the following offspring were observed: 356 wild-type wings, brown bodies; 8 wild-type wings, yellow bodies; 10 vestigial wings, brown bodies; 326 vestigial wings, yellow bodies. The total number of progeny is obtained by adding all the offspring, which is:

356 + 8 + 10 + 326 = 700

The number of recombinant progeny is the sum of the two classes of offspring that exhibit the recombinant phenotypes, which are the wild-type wings and yellow bodies, and the vestigial wings and brown bodies. These are:

8 + 10 = 18

Recombination frequency = (18 / 700) × 100

Recombination frequency = 2.6%

Therefore, the genetic distance between these two genes is 2.6 cM (centimorgans). Therefore, the answer is option D, 2.6.

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