In baseball, each time a player attempts to hit the ball, it is recorded. The ratio of hits compared to total attempts is their batting average. Each player on the team wants to have the highest batting average to help their team the most. For the season so far, Jana has hit the ball 42 times out of 50 attempts. Tasha has hit the ball 9 times out of 10 attempts. Which player has a ratio that means they have a better batting average?

A. Tasha, because she has the highest ratio since [tex]0.9 \ \textgreater \ 0.8[/tex]

B. Tasha, because she has the highest ratio since [tex]\frac{27}{30} \ \textgreater \ \frac{24}{30}[/tex]

C. Jana, because she has the highest ratio since [tex]0.9 \ \textgreater \ 0.8[/tex]

D. Jana, because she has the highest ratio since [tex]\frac{27}{30} \ \textgreater \ \frac{24}{30}[/tex]

To determine which player has a better batting average, we need to compare the ratio of hits to attempts for each player.

First, let's clarify what a batting average is: it is the ratio of successful hits divided by the total number of attempts to hit.

For Jana:
- Hits: 42
- Attempts: 15

Batting average for Jana = Hits / Attempts = 42 / 15 = 2.8

For Tasha:
- Hits: 9
- Attempts: 10

Batting average for Tasha = Hits / Attempts = 9 / 10 = 0.9

Now, we compare the two batting averages:

- Jana's batting average = 2.8
- Tasha's batting average = 0.9

Since 2.8 is greater than 0.9, Jana has a higher batting average.

Therefore, the correct answer is:

Jana, because she has the highest ratio.