High School

In an independent-measures ANOVA, if the F-ratio is [tex]$F = 3.00$[/tex] and the between-treatments variance (MS between) is [tex]$6.00$[/tex], what is the within-treatments variance (MS within)?

A. 3.00
B. 2.00
C. 6.00
D. 1.50

Answer :

Final answer:

In an independent-measures ANOVA, to find the within-treatments variance (MS within) with an F-ratio of 3.00 and a between-treatments variance (MS between) of 6.00, divide MS between by the F-ratio, resulting in an MS within of 2.00. The correct MCQ answer is b) 2.00.

Explanation:

In an independent-measures ANOVA, a given F-ratio calculates the ratio of the variance between treatments to the variance within treatments. Given an F-ratio of 3.00 and a between-treatments variance (MS between) of 6.00, we can solve for the within-treatments variance (MS within) by rearranging the formula for the F-ratio, which is F = MS between / MS within.

To find MS within, we divide the MS between by the F-ratio: MS within = MS between / F-ratio. Substituting in the provided figures, we get MS within = 6.00 / 3.00 = 2.00.

The correct MCQ answer from the options provided is b) 2.00. This represents the within-treatments variance in an independent-measures ANOVA when the F-ratio is 3.00 and the between-treatments variance is 6.00.