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------------------------------------------------ In an ice show, a 43.7 kg skater leaps into the air and is caught by an initially stationary 65.7 kg skater.

(a) What is their final velocity assuming negligible friction and that the leaper's original horizontal velocity was 4.02 m/s?
Options:
- 4.02 m/s
- 2.41 m/s
- 2.67 m/s
- 1.61 m/s

(b) How much kinetic energy is lost?
- 197 J

Final velocity is 1.61m/s. assuming negligible friction and that the leaper's original horizontal velocity was 4.02 m/s and The lost kinetic energy is 197 j

first skater Mass = 43.7 Kg

second skater Mass = 65.7 kg

Initial velocity = 4.02 m/s

conservation of momentum

[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]

175.6+0=109.4v

v=1.61m/s

The lost kinetic energy

[tex][\Delta E=E_2-E_1],[\Delta E)1/2(m_1u_1^2+m_2u_2^2)-1/2(m_1+m_2v^2)[/tex]

by putting data

KINETIC ENERGY=197 j

A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity.

As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item.

To know more about velocity visit : brainly.com/question/16379705

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