High School

In a Young's double-slit experiment, if the distance between the two slits is 7000 and the wavelength of the light used is 2000, what is the fringe spacing?

A) 3500
B) 7000
C) 14000
D) 5000

Answer :

Final Answer:

The fringe spacing in the Young's double-slit experiment is 3500.Option A is answer.

Explanation:

In Young's double-slit experiment, the fringe spacing (Δy) is related to the slit separation (d), the wavelength of light (λ), and the distance between the screen and the slits (D) by the following formula:

Δy = λD / d

We are given:

d = 7000 (distance between slits)

λ = 2000 (wavelength of light)

We are not given the distance between the screen and the slits (D), but it is not needed for this calculation.

Substituting the known values:

Δy = (2000) * D / 7000

Since the answer choices only depend on the ratio of Δy to d, we can cancel out D from both sides:

Δy / d = (2000) * (D / 7000) / d

Therefore, the ratio of fringe spacing to slit separation is always 2000/7000 = 0.5.

Looking at the answer choices, only 3500 is half of 7000.

Therefore, the fringe spacing is 3500.

Option A is answer.