Answer :
Final answer:
Using the Hardy-Weinberg principle and given the frequency of the recessive allele (a) is 0.28, the frequency of the dominant allele (A) is 0.72. The frequency of the AA genotype in the next generation would be 0.72², or 0.5184.
Explanation:
The question pertains to determining the frequency of the AA genotype in a hypothetical dog population given the frequency of a recessive allele (a). To calculate this, we use the Hardy-Weinberg principle, which provides a framework for understanding the genetic structure of a population at equilibrium.
Given the frequency of the recessive allele (a) is 0.28, we can calculate the frequency of the dominant allele (A) as
p = 1 - q,
where q is the frequency of allele a.
This implies
p = 1 - 0.28
= 0.72.
The frequency of the AA genotype is then
p² = 0.72²
= 0.5184.
In summary, with an allele frequency of a = 0.28, the frequency of the AA genotype in the next generation, assuming random mating and no other evolutionary forces at play, would be 0.5184.
