High School

If you shine a laser on two slits with a separation of 0.230 mm, and the diffraction pattern is projected on a screen 5.15 m away, what is the wavelength of the laser light if the fringes are separated by 1.55 cm?

Answer :

Final answer:

The wavelength of the laser light is 7.67 cm.

Explanation:

To calculate the wavelength of the laser light, we can use the formula:

wavelength = (slit separation * screen distance) / fringe separation

Given:

  • Slit separation = 0.230 mm
  • Screen distance = 5.15 m
  • Fringe separation = 1.55 cm

First, let's convert the given values to the same unit:

  • Slit separation = 0.230 mm = 0.023 cm
  • Screen distance = 5.15 m = 515 cm
  • Fringe separation = 1.55 cm

Now, substitute the values into the formula:

wavelength = (0.023 cm * 515 cm) / 1.55 cm

Simplifying the expression:

wavelength = 7.67 cm

Therefore, the wavelength of the laser light is 7.67 cm.

Learn more about calculating the wavelength of laser light using the double-slit experiment here:

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Final answer:

The wavelength of the laser light is 0.076 m.

Explanation:

To calculate the wavelength of the laser light, we can use the formula:

wavelength = (slit separation * screen distance) / fringe separation

Given:

  • Slit separation = 0.230 mm = 0.00023 m
  • Screen distance = 5.15 m
  • Fringe separation = 1.55 cm = 0.0155 m

Substituting the given values into the formula:

wavelength = (0.00023 m * 5.15 m) / 0.0155 m

Simplifying the expression:

wavelength = 0.00023 m * 5.15 m / 0.0155 m

wavelength = 0.076 m

Therefore, the wavelength of the laser light is 0.076 m.

Learn more about calculating the wavelength of laser light using the double-slit experiment here:

https://brainly.com/question/31807318

#SPJ14

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