Answer :
Final answer:
Without additional details about the beam's geometry and load distribution, we cannot determine the absolute maximum bending stress in aluminum and steel from the information provided. Ultimate stresses are given, but they are not sufficient for direct calculation.
Explanation:
To determine the absolute maximum bending stress developed in the aluminum and steel when w=700lb/ft, we need additional information such as the beam's geometry (moment of inertia) and the length over which the load is applied. Nonetheless, the breaking stress or ultimate stress of a material is the value of stress at the fracture point. The given problem does not provide enough information to calculate the bending stress directly. For a quick estimation, using the provided ultimate stresses for aluminum (2.2 × 108 Pa) and steel (up to 20.0 × 108 Pa), and assuming rods of 1-in² cross-sectional area, the breaking loads are 3.2 × 104 lb for aluminum and about nine times larger for steel. To calculate the maximum bending stress, you would typically use the formula σ = Mc/I, where σ is the bending stress, M is the moment, c is the distance from the neutral axis to the outer fiber, and I is the moment of inertia. However, due to the lack of specific values for M, c, and I, as well as the load distribution, we cannot provide an exact answer for the options a) 2000psi, b) 2500psi, c) 3000psi, d) 3500psi without further information.
