Answer :
To solve the problem, we first use the formula for pressure:
[tex]$$
P = \frac{F}{A},
$$[/tex]
where:
- [tex]$F$[/tex] is the total force,
- [tex]$A$[/tex] is the area.
Given that the force exerted by the water is [tex]$450\ \text{N}$[/tex] and the bottom area of the container is [tex]$2\ \text{m}^2$[/tex], we calculate the pressure as follows:
[tex]$$
P = \frac{450\ \text{N}}{2\ \text{m}^2} = 225\ \text{Pa}.
$$[/tex]
Since [tex]$1\ \text{kPa} = 1000\ \text{Pa}$[/tex], we convert the pressure from Pascals to kilopascals:
[tex]$$
225\ \text{Pa} = \frac{225}{1000}\ \text{kPa} = 0.225\ \text{kPa}.
$$[/tex]
Thus, the water pressure at the bottom of the container is [tex]$0.225\ \text{kPa}$[/tex], which corresponds to option (b).
[tex]$$
P = \frac{F}{A},
$$[/tex]
where:
- [tex]$F$[/tex] is the total force,
- [tex]$A$[/tex] is the area.
Given that the force exerted by the water is [tex]$450\ \text{N}$[/tex] and the bottom area of the container is [tex]$2\ \text{m}^2$[/tex], we calculate the pressure as follows:
[tex]$$
P = \frac{450\ \text{N}}{2\ \text{m}^2} = 225\ \text{Pa}.
$$[/tex]
Since [tex]$1\ \text{kPa} = 1000\ \text{Pa}$[/tex], we convert the pressure from Pascals to kilopascals:
[tex]$$
225\ \text{Pa} = \frac{225}{1000}\ \text{kPa} = 0.225\ \text{kPa}.
$$[/tex]
Thus, the water pressure at the bottom of the container is [tex]$0.225\ \text{kPa}$[/tex], which corresponds to option (b).
