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------------------------------------------------ If the initial partial pressures are \( P_{\text{{PH}}_3} = 0.0276 \, \text{atm} \), \( P_{\text{{P}}_2} = 0.867 \, \text{atm} \), and \( P_{\text{{H}}_2} = 0.512 \, \text{atm} \), calculate \( Q_p \).

a) \( Q_p > 1 \)
b) \( Q_p = 1 \)
c) \( 0 < Q_p < 1 \)
d) \( Q_p = 0 \)

To calculate Qₚ, divide the product of the partial pressures of the products by the product of the partial pressures of the reactants. In this case, Qₚ = 15.891, which is greater than 1.

Explanation:

To calculate Qₚ, we need to divide the product of the partial pressures of the products by the product of the partial pressures of the reactants. In this case, Qₚ is calculated as: Qₚ = (P₂ * Pₕ₂) / (Pₚₕ₃). Plugging in the given values, the calculation becomes: Qₚ = (0.867 * 0.512) / (0.0276). Calculating this gives us a value of Qₚ = 15.891, which is greater than 1.

Therefore, the correct answer is a) Qₚ > 1.