Answer :
Final answer:
The initial speed of the 6.00 kg block is 0 m/s.
Explanation:
According to the information provided, we have two blocks in contact on a frictionless surface. The mass of the first block is 2.0 kg, and the mass of the second block is 6.0 kg. The first block is initially at rest, while the second block is moving.
Since the blocks are in contact, they are subject to the same net force. Using Newton's second law (F = ma), we can equate the net force acting on both blocks:
m1a = m2a2
Substituting the given masses, we have:
2.0 kg × 0 = 6.0 kg × a2
This equation tells us that the acceleration of the second block (a2) is zero, which means it is not moving. Therefore, the initial speed of the 6.0 kg block is 0 m/s.
