Answer :
The mass of NO formed is 44.1 grams.
Mass of NH3 = 25.0 g
Mass of O2 = 38.6 g
We need to find the mass of NO formed.
Balanced chemical reaction equation:
[tex]4NH3 + 5O2 → 4NO + 6H2O[/tex]
Molecular weights:
NH3 = 14 + 3 = 17
O2 = 16 + 16 = 32
NO = 14 + 16 = 30
As per the balanced chemical reaction equation, 4 moles of NH3 reacts with 5 moles of O2 to produce 4 moles of NO and 6 moles of H2O.
Molar mass of NH3 = 17 g/mol
Molar mass of O2 = 32 g/mol
Molar mass of NO = 30 g/mol
Number of moles of NH3 = Mass / Molar mass
Number of moles of NH3 = 25.0 g / 17 g/mol
Number of moles of NH3 = 1.47 moles
Number of moles of O2 = Mass / Molar mass
Number of moles of O2 = 38.6 g / 32 g/mol
Number of moles of O2 = 1.21 moles
NH3 is the limiting reagent in this reaction as it produces fewer moles of NO, i.e., 1.47 moles.
NO formed from 1.47 moles of NH3 = 1.47 × 4/4 = 1.47 moles.
Mass of NO = Number of moles × Molar mass
Mass of NO = 1.47 moles × 30 g/mol
Mass of NO = 44.1 g
Therefore, 44.1 grams is the mass of NO formed.
To learn more about mass, refer below:
https://brainly.com/question/11954533
#SPJ11
