If someone falls at a rate of 3 kg/s, how long in seconds will it take someone with a mass of 103 lb to fall off a hill? (Note: Convert the mass from pounds to kilograms before calculating the time.)

To calculate the time it takes for the person to fall, we first need to convert their mass from pounds to kilograms. We know that 1 lb is approximately equal to 0.453592 kg. Therefore, the person's mass is 103 lb × 0.453592 kg/lb = 46.72 kg.

Now, we can use the formula for acceleration due to gravity: acceleration = force/mass. Since the person is falling under the influence of gravity, the force is their weight, which is mass × gravity. On Earth, gravity is approximately 9.8 m/s^2. So, the person's weight is 46.72 kg × 9.8 m/s^2 = 458.56 N.

Now, we can use the formula for acceleration: acceleration = force/mass = 458.56 N / 46.72 kg ≈ 9.8 m/s^2. Since the person is falling freely, their acceleration is equal to the acceleration due to gravity. Now, we can use the equation for velocity: velocity = initial velocity + acceleration × time. Since the person is starting from rest, the initial velocity is 0 m/s. Therefore, velocity = 0 m/s + (9.8 m/s^2) × time. Rearranging the equation to solve for time, we get time = velocity/acceleration = 0 m/s ÷ (9.8 m/s^2) ≈ 444.33 s.

Therefore, it would take approximately 444.33 seconds for a person with a mass of 103 lb to fall off a hill if they were falling at a rate of 3 kg/s.