Answer :
OQ is 11 if OP=17 and QP=6. This is obtained by using Segment Addition Postulate.
What is Segment Addition Postulate ?
If Q is between O and P, then OQ + QP = OP.
Find OQ + QP and OQ:
Given, OP=17 and QP=6
According to Segment Addition Postulate,
OQ + QP = OP
OQ + 6 = 17
OQ= 17-6 =11
OQ = 11
∴ OQ + QP =17 and OQ = 11
Hence the value of OQ is 11 when OP is 17 and QP is 6.
Learn more about Segment Addition Postulate here:
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Answers:
OQ + QP = OP
OQ = 11
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Explanation:
The smaller pieces OQ and QP glue together to form the larger segment OP. This is effectively what the Segment Addition Postulate says. This only works if all three points are on the same single line segment.
We know that OP is 17, so QP = 6 adds to the other unknown piece to get 17. The other piece must be 11 units long. Algebraically you could write,
OQ + QP = OP
OQ + 6 = 17
OQ + 6-6 = 17-6 ... subtracting 6 from both sides
OQ = 11
