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------------------------------------------------ If a wire of length 4 meters is carrying a current of [tex]2A[/tex], calculate the magnetic field strength at a distance of 3 meters from the wire.

A) [tex]3.14 \times 10^{-7} \, \text{T}[/tex]
B) [tex]6.28 \times 10^{-7} \, \text{T}[/tex]
C) [tex]9.42 \times 10^{-7} \, \text{T}[/tex]
D) [tex]1.57 \times 10^{-6} \, \text{T}[/tex]

To calculate the magnetic field strength at a distance of 3 meters from the wire, we can use Ampere's Law. Ampere's Law states that the magnetic field created by a current-carrying wire is directly proportional to the current and inversely proportional to the distance from the wire.

B = μ0 * (I / 2π * r)

where B is the magnetic field, μ0 is the permeability of free space (approximately 4π×10-7 Tm/A), I is the current, and r is the distance from the wire.

Plugging in the values, we get:

B = (4π×10-7 * 2A) / (2π * 3m) = 4×10-7T.

Therefore, the magnetic field strength at a distance of 3 meters from the wire is approximately 4×10-7T.