Answer :
The rotations per second will triple and she will rotate thrice per second.
- The rotation of the trapeze artist is not influenced by any external forces or torques during the motion.
- Therefore, her total rotational momentum ([tex]I \omega[/tex]) should be conserved throughout the motion or during a transition.
- This question checks your primary understanding of this concept and you have to simply use the formula associated with the rotational momentum from one position to the other (expansion and contraction).
- The formula is like this, [tex]I_1 \omega_1 = I_2 \omega_2 = \text{constant}[/tex]. Here [tex]I[/tex] and [tex]\omega[/tex] have the usual meanings.
- Therefore, the calculation would look like the following,
[tex]\begin{aligned}\\\\I_1\omega_1&= I_2 \omega_2\\\\I\omega &= \frac{I}{3}.\omega_2\cdots(I\, \text{could be cancelled out})\\\\\omega_2 &= 3I\end{aligned}[/tex]
- Since the initial rotation is one round per second the final rotation which is thrice will mean 3 rotations per second.
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