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If a pump flow output is measured to be 45 gpm at 4,500 psi, its hydraulic power output can be calculated to be:

Select one:

A. 118 kW
B. 118 hp
C. 118 gpm/hr
D. 118 kW/hr

Answer :

To calculate the hydraulic power output of a pump, we use the following formula:

[tex]\[ \text{Hydraulic Power (HP)} = \frac{\text{Flow Rate (GPM)} \times \text{Pressure (PSI)}}{1714} \][/tex]

Where:
- Flow Rate is in gallons per minute (GPM).
- Pressure is in pounds per square inch (PSI).
- 1714 is the constant used to convert the units of GPM and PSI to horsepower (HP).

For the given problem:
- The flow rate of the pump is 45 gallons per minute.
- The pressure is 4500 pounds per square inch.

Plug these values into the formula:

[tex]\[ \text{Hydraulic Power (HP)} = \frac{45 \times 4500}{1714} \][/tex]

This calculation yields approximately 118 horsepower (HP).

Therefore, the correct option for the hydraulic power output is:

b. 118 hp

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