Answer :
To determine which bird beats its wings faster, we need to calculate the rate of beats per second for each bird.
Bird A: Beats its wings 3000 times in 60 seconds.
- To find the rate in beats per second, divide the total beats by the time in seconds:
[tex]\text{Rate of Bird A} = \frac{3000 \text{ beats}}{60 \text{ seconds}} = 50 \text{ beats/second}[/tex]
Bird B: Beats its wings 180 times in 15 seconds.
- Similarly, to find the rate in beats per second, divide the total beats by the time in seconds:
[tex]\text{Rate of Bird B} = \frac{180 \text{ beats}}{15 \text{ seconds}} = 12 \text{ beats/second}[/tex]
By comparing the two rates:
- Bird A has a wing beat rate of 50 beats per second.
- Bird B has a wing beat rate of 12 beats per second.
Therefore, Bird A beats its wings faster than Bird B.
