Answer :
The height of the object above the ground is 10 m.
The given parameters;
- gravitational potential energy of the rock, P.E = 196 J
- mass of the rock, m = 2 kg
- acceleration due to gravity, g = 9.8 m/s²
Potential energy of an object is the energy possessed by an object due to its position.
The height of the object is calculated as follows;
P.E = mgh
where;
h is the height of the object above the ground
[tex]h = \frac{P.E}{mg} \\\\h = \frac{196}{9.8 \times 2} \\\\h = 10 \ m[/tex]
Thus, the height of the object above the ground is 10 m.
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Final answer:
The 2 kg rock has a height of 10 metres above the ground if its potential energy is 196 J.
Explanation:
The question relates to the calculation of height from the given gravitational potential energy and mass using the physics concept of potential energy. The formula for Potential Energy (PE) is PE = mgh, where m: mass of the object, g: gravitational force (which is 9.8 m/s² on Earth), and h: height of the object above the ground.
We rearrange the formula to calculate the height: h = PE / (mg). Now substitute the given values into formula: h = 196 J / (2 kg * 9.8 m/s²), which gives the height as 10 metres.
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