Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ If 98.5 mol of an ideal gas is at 5.37 atm and 48.60°C, what is the volume of the gas in liters?

The question is about calculating the volume of an ideal gas at a specific pressure and temperature using the ideal gas law. The calculated volume of the 98.5 mol of gas under these conditions is found to be 4922.05 liters.

Explanation:

The subject of this question is ideal gas and it involves using the ideal gas law, PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature in Kelvin. First, convert the temperature from Celsius to Kelvin by adding 273.15 to 48.60. This gives 321.75 K.

Then, you can rearrange the ideal gas law formula to solve for volume: V = nRT / P. If you substitute the given values: V = 98.5 mol * 0.0821 L·atm/mol·K * 321.75 K / 5.37 atm = 4922.05 liters. So, the volume of the 98.5 mol of the ideal gas at the given temperature and pressure is 4922.05 liters.

Learn more about Ideal Gas Law here:

https://brainly.com/question/30458409

#SPJ11