Answer :
The vapor pressure of the solution is approximately 9.75 mmHg. To calculate vapor pressure of the solution, we can use Raoult's law:
Now,
First, find the moles of glucose (solute) and water (solvent):
Moles of Glucose = 79.5 g / 180.2 g/mol ≈ 0.441 mol
Moles of Water = 38.4 g / 18.015 g/mol ≈ 2.132 mol
Next, calculate the mole fractions:
Mole Fraction of Glucose = 0.441 / (0.441 + 2.132) ≈ 0.171
Mole Fraction of Water = 2.132 / (0.441 + 2.132) ≈ 0.829
The vapor pressure of pure water at given temperature is typically around 23.8 mmHg.
Raoult's law:-
Vapor Pressure of Solution = (0.829 * 23.8 mmHg) + (0.171 * 0 mmHg) ≈ 19.75 mmHg
Learn more about Raoult's law:-
https://brainly.com/question/33940059
#SPJ4
