Answer :
mass of solute = 35.8 g
mass of solvent = 184 g
w ( % ) = 35.8 / 35.8 + 184
w ( % ) = 35.8 / 219.8
= 0.1628 x 100 => 16.28 %
mass of solvent = 184 g
w ( % ) = 35.8 / 35.8 + 184
w ( % ) = 35.8 / 219.8
= 0.1628 x 100 => 16.28 %
Answer : The concentration of solution in percent by mass is 16.3 %
Explanation :
Percent by mass : It means that the mass of solute present in the mixture and multiply by 100.
Given:
Mass of LiCl = 35.8 g
Mass of water = 184 g
First we have to calculate the mass of mixture.
Mass of mixture = Mass of LiCl + Mass of water
Mass of mixture = 35.8 g + 184 g
Mass of mixture = 219.8 g
Now we have to calculate the concentration of solution in percent by mass.
[tex]\text{Concentration of solution in percent by mass}=\frac{\text{Mass of }LiCl}{\text{Mass of mixture}}\times 100[/tex]
[tex]\text{Concentration of solution in percent by mass}=\frac{35.8g}{219.8g}\times 100=16.3\%[/tex]
Therefore, the concentration of solution in percent by mass is 16.3 %
