High School

If 35.5 mol of an ideal gas is at 9.07 atm at 65.70 ∘C, what is the volume of the gas?

Answer :

The volume of the gas is approximately 1047.86 liters.

The volume of an ideal gas can be calculated using the ideal gas law equation, which is PV = nRT. In this equation, P represents the pressure of the gas, V represents the volume of the gas, n represents the number of moles of the gas, R is the ideal gas constant, and T represents the temperature of the gas in Kelvin.

To find the volume of the gas, we need to rearrange the equation to solve for V. So the equation becomes V = (nRT) / P.

Given:
n = 35.5 mol
P = 9.07 atm
T = 65.70 °C

First, we need to convert the temperature from Celsius to Kelvin. To do this, we add 273.15 to the Celsius temperature.

T = 65.70 + 273.15 = 338.85 K

Next, we can substitute the given values into the equation and calculate the volume of the gas.

V = (35.5 mol * 0.0821 L*atm/(mol*K) * 338.85 K) / 9.07 atm

Using the ideal gas constant, R, which is 0.0821 L*atm/(mol*K), we can simplify the equation further:

V = (35.5 * 0.0821 * 338.85) / 9.07
V ≈ 1047.86 L

Therefore, the volume of the gas is approximately 1047.86 liters.

Learn more about the gas volume here:

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