Answer :
Answer:
New volume of chlorine gas (V2) = 179 ml (Approx)
Explanation:
Given:
Volume of chlorine gas (V1) = 193 ml
Temperature of chlorine gas (T1) = 21°C = 21 + 273 = 294 k
New temperature of chlorine gas (T2) = 0°C = 0 + 273 = 273 k
Find:
New volume of chlorine gas (V2) = ?
Computation:
Using charle's law
V1 / T1 = V2 / T2
193 / 294 = V2 / 273
V2 = 179.21
New volume of chlorine gas (V2) = 179 ml (Approx)
Using Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvins, we find that the volume of 193 ml of chlorine gas at 21 degrees Celsius would decrease to approximately 179.60 ml if the temperature is lowered to 0 degrees Celsius.
If 193 ml of chlorine gas is collected at 21 degrees Celsius and we want to determine what volume it would have if the temperature dropped to 0 degrees Celsius, we can use Charles's Law to find the answer. Charles's Law states that the volume of a given amount of gas is directly proportional to its temperature on the Kelvin scale, provided the pressure and the amount of gas remain constant.
To use Charles's law, we first convert the temperatures from Celsius to Kelvin by adding 273.15. Therefore, 21 degrees Celsius is 294.15 Kelvin, and 0 degrees Celsius is 273.15 Kelvin.
Next, we set up the equation in the form of V₁/T₁ = V₂/T₂:
V₁ = 193 ml (initial volume)
T₁ = 294.15 K (initial temperature)
T₂ = 273.15 K (final temperature)
V₂ = ? (final volume we are solving for)
Plugging the values into the equation:
193 ml / 294.15 K = V₂ / 273.15 K
Now solve for V₂:
V₂ = (193 ml / 294.15 K) x 273.15 K
After calculating, V₂ = 179.60 ml (approximate)
So, if the temperature of the chlorine gas drops from 21 degrees Celsius to 0 degrees Celsius, its new volume would be approximately 179.60 ml.
