High School

If 101.0 J of heat is supplied to a sample of steel and the temperature of the sample increases by [tex]26.3^\circ C[/tex], what is the heat capacity of the sample of steel?

A. 38.4 J/C
B. 3.84 J/C
C. 0.384 J/C
D. 0.261 J/C

Answer :

Final answer:

The heat capacity of the steel sample is calculated by dividing the heat supplied (101.0 J) by the change in temperature (26.3°C). Using this method, we find the heat capacity to be 3.84 J/C. Therefore, the correct option is "b. 3.84 J/C".

Explanation:

The question is asking for the heat capacity of a sample of steel.

This is a concept in Physics, particularly thermodynamics.

The formula for calculating heat capacity (C) is Q = C ∆T, where Q is the heat supplied, C is the heat capacity, and ∆T is the change in temperature.

In this particular problem:

Q = 101.0 J (Joules)

∆T = 26.3°C

Now, we simply rearrange the formula to solve for C (heat capacity):

C = Q / ∆T = 101.0 J / 26.3°C = 3.84 J/C

So, the heat capacity of the sample of steel is 3.84 J/C.

Hence, the answer is option "b. 3.84 J/C".

Heat capacity, often denoted as "C," is a physical property that quantifies the amount of heat energy required to change the temperature of a substance by a certain amount.

It measures the ability of a substance to absorb or release heat energy without experiencing a significant change in temperature.

Heat capacity is an essential concept in thermodynamics and is used to describe how substances respond to changes in temperature.

In summary, heat capacity is a crucial concept in thermodynamics that helps describe how substances respond to changes in temperature and how much heat energy is required to achieve a given temperature change.

Learn more about Heat Capacity:

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