High School

If 10 g of oxygen gas is in a 2.00 L container at 50°C, what is the pressure in the container? Round to one decimal place.

Answer :

13.3 kPa. The ideal gas law is used to calculate the pressure of a gas in a container: PV = nRT

Ideal gas law

Where

P is the pressure,

V is the volume,

n is the number of moles of gas,

R is the ideal gas constant, and

T is the temperature.

We can rearrange the equation to solve for P:

P = (nRT) / V

We are given the

volume (2.00 L),

temperature (50 C), and

mass (10 g).

We can convert the mass to moles using the molar mass of oxygen (O2):

n = 10 g / (32 g/mol) = 0.312 mol

The ideal gas constant is 8.314 J/(mol.K).

We can convert the temperature from Celsius to Kelvin (K), which is done by adding 273.15 to the Celsius temperature:

T = 50 + 273.15 = 323.15 K

We can now plug these values into the ideal gas law:

P = (0.312 mol * 8.314 J/(mol.K) * 323.15 K) / 2.00 L

P = 13.3 kPa

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