High School

Identify the 16th term of a geometric sequence where [tex]$a_1 = 4$[/tex] and [tex]$a_8 = -8,748$[/tex].

A. -172,186,884
B. -57,395,628
C. 57,395,628
D. 172,186,884

Answer :

Answer:

−57,395,628

Step-by-step explanation:
First, determine the common ratio by the equation,
an = a1 x r^(n - 1)
Substituting the values,
-8748 = 4 x r^(8 - 1)
The value of r is -3. By the same equation, the 16th term is,
a16 = 4 x (-3)^(16 - 1)
a16 = -57,395,628
Thus, the answer is the second choice.

Other Questions