High School

I have 2 bags of counters.

The 1st bag contains: 2 red counters, 1 blue counter.
The 2nd bag contains: 1 red counter, 1 blue counter, 2 yellow counters.

A. What is the probability that the 2 counters drawn will be the same color?
B. What is the probability that the 2 counters drawn will be red?

Answer :

Final answer:

The probability that the 2 counters will be the same color is 1/4. The probability that the 2 counters will be red is 2/9.

Explanation:

To find the probability that the 2 counters will be the same color, we need to consider the possible combinations of counters from both bags.

A. The probability that the 2 counters will be the same color:

  1. Count the number of counters of each color from both bags. The 1st bag has 2 red counters and 1 blue counter, while the 2nd bag has 1 red counter and 1 blue counter.
  2. Calculate the probability of getting 2 red counters:
  • Probability of getting a red counter from the 1st bag: 2/3
  • Probability of getting a red counter from the 2nd bag: 1/4
  • Total probability = (2/3) * (1/4) = 2/12 = 1/6
Calculate the probability of getting 2 blue counters:
  • Probability of getting a blue counter from the 1st bag: 1/3
  • Probability of getting a blue counter from the 2nd bag: 1/4
  • Total probability = (1/3) * (1/4) = 1/12
Add the probabilities of getting 2 red counters and 2 blue counters to get the final probability:
  • Final probability = 1/6 + 1/12 = 2/12 + 1/12 = 3/12 = 1/4

B. The probability that the 2 counters will be red:

  1. Count the number of red counters from both bags. The 1st bag has 2 red counters and the 2nd bag has 1 red counter.
  2. Calculate the total number of counters from both bags:
  • Total number of counters = number of counters in the 1st bag + number of counters in the 2nd bag = 2 + 1 = 3
Calculate the probability of getting 2 red counters:
  • Probability of getting a red counter from the 1st bag: 2/3
  • Probability of getting a red counter from the 2nd bag: 1/3
  • Total probability = (2/3) * (1/3) = 2/9

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