College

How much soil with 51% sand do you need to add to 10 yd³ of soil with 21% sand in order to make a soil with 31% sand?

Answer :

Final answer:

To create the desired soil mixture with 31% sand, the student must solve an equation that represents the mixing of two soils with different sand percentages. By setting up the appropriate equation and solving for the unknown quantity, the student can determine the amount of soil needed.

Explanation:

The subject in question is Mathematics, more specifically, it involves finding the quantity of a mixture using percentages. The student is asked to determine how to make a soil mixture with a desired percentage of sand by adding two different types of soil together. This involves setting up an equation based on the percentages of sand in each type of soil and the desired final percentage.

Step-by-step process to solve the problem:

Let the amount of soil with 51% sand that needs to be added be x yards.

Calculate the total amount of sand in the 10 yards of soil with 21% sand: 10 yards * 21% = 2.1 yards of sand.

Set up the equation to find out how much sand content will be present after adding x yards of the 51% sand soil: 51% of x yards of soil (0.51x) + 2.1 yards (from the initial 10 yards of 21% sand soil) = 31% of the total soil (10 yards + x yards).

Solve the equation for x.

By solving this equation, you will be able to find the value for x, which represents the yardage of the soil with 51% sand that you need to add to the 10 yards of soil with 21% sand to create a soil mixture with 31% sand content.