Answer :
The acceleration given to a 36 kg person with a 0.70 N push on a trapeze is calculated using Newton's second law of motion. By dividing the force by the mass (0.70 N / 36 kg), the acceleration is found to be approximately 0.01944 m/s².
The acceleration given to a 36 kg person with a 0.70 N push on a trapeze can be calculated using Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration (F = m*a). To find the acceleration (a), we can rearrange the formula to a = F/m.
Using the values provided:
- Force (F) = 0.70 N
- Mass (m) = 36 kg
By plugging these values into the formula, we get:
a = F / m
a = 0.70 N / 36 kg
a = 0.01944 m/s² (rounded to 5 decimal places)
Therefore, the acceleration given to the person is approximately 0.01944 m/s².
