Answer :
Sure, let's solve the question step-by-step.
We need to find out how many moles of MgS₂O₃ are in 197 grams of the compound.
Step 1:
First, we need to determine the molar mass (molecular weight) of MgS₂O₃. This involves adding up the atomic masses of each element in the compound based on how many atoms of each element are present.
Atomic masses:
- Magnesium (Mg) = 24.305 g/mol
- Sulfur (S) = 32.065 g/mol
- Oxygen (O) = 15.999 g/mol
Step 2:
Now, calculate the molar mass of MgS₂O₃:
- 1 atom of Magnesium: 24.305 g/mol
- 2 atoms of Sulfur: [tex]\(2 \times 32.065\)[/tex] g/mol
- 3 atoms of Oxygen: [tex]\(3 \times 15.999\)[/tex] g/mol
So, the molar mass of MgS₂O₃ is:
[tex]\[ 24.305 + (2 \times 32.065) + (3 \times 15.999) \][/tex]
[tex]\[ = 24.305 + 64.13 + 47.997 \][/tex]
[tex]\[ = 136.432 \text{ g/mol} \][/tex]
Step 3:
Now, we'll use the given mass of the compound (197 grams) to find the number of moles.
The formula to find the number of moles is:
[tex]\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \][/tex]
Using the values we have:
[tex]\[ \text{Number of moles} = \frac{197 \text{ g}}{136.432 \text{ g/mol}} \][/tex]
[tex]\[ = 1.4439427700246275 \][/tex]
Step 4:
Therefore, there are approximately [tex]\(1.44\)[/tex] moles of MgS₂O₃ in 197 grams of the compound.
We need to find out how many moles of MgS₂O₃ are in 197 grams of the compound.
Step 1:
First, we need to determine the molar mass (molecular weight) of MgS₂O₃. This involves adding up the atomic masses of each element in the compound based on how many atoms of each element are present.
Atomic masses:
- Magnesium (Mg) = 24.305 g/mol
- Sulfur (S) = 32.065 g/mol
- Oxygen (O) = 15.999 g/mol
Step 2:
Now, calculate the molar mass of MgS₂O₃:
- 1 atom of Magnesium: 24.305 g/mol
- 2 atoms of Sulfur: [tex]\(2 \times 32.065\)[/tex] g/mol
- 3 atoms of Oxygen: [tex]\(3 \times 15.999\)[/tex] g/mol
So, the molar mass of MgS₂O₃ is:
[tex]\[ 24.305 + (2 \times 32.065) + (3 \times 15.999) \][/tex]
[tex]\[ = 24.305 + 64.13 + 47.997 \][/tex]
[tex]\[ = 136.432 \text{ g/mol} \][/tex]
Step 3:
Now, we'll use the given mass of the compound (197 grams) to find the number of moles.
The formula to find the number of moles is:
[tex]\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \][/tex]
Using the values we have:
[tex]\[ \text{Number of moles} = \frac{197 \text{ g}}{136.432 \text{ g/mol}} \][/tex]
[tex]\[ = 1.4439427700246275 \][/tex]
Step 4:
Therefore, there are approximately [tex]\(1.44\)[/tex] moles of MgS₂O₃ in 197 grams of the compound.
