High School

How many moles of [tex]C_3H_8(g)[/tex] were burned if 100.8 liters of [tex]CO_2[/tex] are formed at 0.00 °C and 1.00 atm of pressure according to the reaction:

\[ C_3H_8(g) + 5 O_2(g) \rightarrow 3CO_2(g) + 4H_2O(g) \]

Answer :

Final answer:

To calculate the number of moles of C3H8 that were burned, use the volume ratios from the balanced equation. Set up a proportion using the given volumes of C3H8 and CO2, and solve for the number of moles of C3H8. Use Avogadro's number to convert the volume of CO2 to moles.

Explanation:

According to the balanced equation, one volume of C3H8 reacts with five volumes of O2. Therefore, to calculate the number of moles of C3H8 that were burned, we can use the volume ratios from the equation. Since 2.7 L of C3H8 requires 13.5 L of O2, we can set up a proportion and solve for the number of moles of C3H8:

(2.7 L C3H8 / 13.5 L O2) = (x moles C3H8 / 100.8 L CO2)

Simplifying the proportion gives us:

x moles C3H8 = (2.7 L C3H8 / 13.5 L O2) * 100.8 L CO2

Using Avogadro's number, we can convert the volume of CO2 to moles:

x moles C3H8 = (2.7 L C3H8 / 13.5 L O2) * 100.8 L CO2 * (1 mole CO2 / 22.4 L CO2)

Finally, we calculate the number of moles of C3H8:

x moles C3H8 = (2.7 L C3H8 / 13.5 L O2) * 100.8 L CO2 * (1 mole CO2 / 22.4 L CO2)

Learn more about Calculating moles from volume ratios here:

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