High School

How many moles of sulfur dioxide are in 73.0 grams of sulfur dioxide? Report your answer to the correct significant figures.

A. 1.1 mol
B. 1.92 mol
C. 1.14 mol
D. 38.1 mol

How many grams of carbon dioxide are in 1.00 mole of carbon dioxide? Report the answer to 3 significant figures.

A. 28.0 g
B. 32.0 g
C. 44.0 g
D. 88.0 g

Answer :

Hence, 1.14 moles of Sulfur dioxide in 73 g and 44 grams of Carbon dioxide are in 1 mole.

The first question asks us to find the number of moles of sulfur dioxide in 73.0 grams. We can use the formula:

Moles = mass / molar mass,

where molar mass is the sum of the atomic masses of all the elements in the compound. For sulfur dioxide, the molar mass is 32.07 g/mol for sulfur and 2*16.00 g/mol for oxygen, giving a total of 64.07 g/mol.

Plugging in the given mass of 73.0 g and the molar mass, we get the number of moles to be 1.14 mol, which corresponds to option (c).


The second question asks us to find the mass of carbon dioxide in 1.00 mole. We can use the formula:

Mass = moles * molar mass,

where the molar mass is 12.01 g/mol for carbon and 2*16.00 g/mol for oxygen, giving a total of 44.01 g/mol for carbon dioxide. Plugging in the given number of moles of 1.00 mol and the molar mass, we get the mass to be 44.0 g, which corresponds to option (c).

Therefore, the answer to both questions is (c) 1.14 mol for the first question and 44.0 g for the second question.

Know more about Moles here:

https://brainly.com/question/24191825

#SPJ11