College

How many moles of NaCl are present in 600 mL of a 1.55 M solution?

Answer :

To find the number of moles of NaCl present in 600 mL of a 1.55 M solution, follow these steps:

1. Understand the Relationship: The number of moles of a solute in a solution can be calculated using the formula:
[tex]\[
\text{moles} = \text{molarity} \times \text{volume (in liters)}
\][/tex]
where molarity is given in moles per liter (M), and volume needs to be in liters.

2. Convert Volume to Liters: Since the given volume is in milliliters, convert it to liters by dividing by 1000:
[tex]\[
600 \, \text{mL} = \frac{600}{1000} \, \text{L} = 0.6 \, \text{L}
\][/tex]

3. Multiply by Molarity: Multiply the volume in liters by the molarity to find the moles of NaCl:
[tex]\[
\text{moles of NaCl} = 1.55 \, \text{M} \times 0.6 \, \text{L}
\][/tex]

4. Calculate: Perform the multiplication:
[tex]\[
\text{moles of NaCl} = 0.93
\][/tex]

Therefore, there are approximately 0.93 moles of NaCl present in 600 mL of a 1.55 M solution.