High School

How many moles of helium occupy a volume of 5.00 L at 227 °C and 5.00 atm?

A. 5.00 mol
B. 1.64 mol
C. 25.0 mol
D. 0.609 mol

Answer :

The number of moles of helium gas present in a given volume at a specified temperature and pressure is 1.64 mol. The correct answer is b) 1.64 mol.



The ideal gas law is expressed as PV = nRT, where P represents pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. To determine the number of moles, we can rearrange this equation

n = PV/RT

Plugging in the given values, we get:

n = (5.00 atm)(5.00 L)/((0.0821 L atm/mol K)(500 K))

Note that we had to convert the temperature from °C to K by adding 273 to get 500 K.

Solving for n, we get:

n = 1.64 mol

Therefore, the number of moles of helium that occupy a volume of 5.00 L at 227 °C and 5.00 atm is 1.64 mol.

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