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------------------------------------------------ How many lone pairs are there in [tex]Ba_3N_2[/tex]?

How many double bonds are there in [tex]Ba_3N_2[/tex]?

How many single bonds are there in [tex]Ba_3N_2[/tex]?

How many bonds are there?

How many valence electrons are there?

Ba3N2 is an ionic compound composed of barium ions (Ba2+) and nitride ions (N3-). There are no lone pairs in Ba3N2, no double pairs or double bonds, and six single ionic bonds. The compound has a total of six ionic bonds and a total of 16 valence electrons.

Explanation:

Ba3N2 is an ionic compound composed of barium ions (Ba2+) and nitride ions (N3-).

1. Lone pairs: Since the nitride ion has a full octet, there are no lone pairs of electrons in Ba3N2.

2. Double pairs: Ba3N2 does not have any double bonds, as it consists of ions that form ionic bonds.

3. Single bonds: Each barium ion (Ba2+) forms a single ionic bond with two nitride ions (N3-), resulting in six single bonds in Ba3N2.

4. Total bonds: Therefore, Ba3N2 has a total of six ionic bonds.

5. Valence electrons: Barium (Ba) has two valence electrons, and nitrogen (N) has five valence electrons. Since there are three barium ions (+2 charge each) and two nitride ions (-3 charge each), the total valence electrons in Ba3N2 are: (2 x 3) + (5 x 2) = 16 valence electrons.