High School

How many grams of water (18.02 g/mol) would contain [tex]6.54 \times 10^{24}[/tex] hydrogen atoms?

A. 10.9 g
B. 5.43 g
C. 0.301 g
D. 97.9 g
E. [tex]3.27 \times 10^{24}[/tex] g

Answer :

The correct answer is option D.

To find the mass of water corresponding to a given number of hydrogen atoms, we calculate the molar mass of water and use it to determine the mass. The correct answer is 97.9 g.

Explanation:

To find the mass of water that would contain a given number of hydrogen atoms, we need to calculate the molar mass of water and use it to determine the mass corresponding to the given number of hydrogen atoms.

The molar mass of water (H2O) is calculated by adding the atomic masses of hydrogen (H) and oxygen (O):
Molar mass of water = 2(1.008 g/mol) + 16.00 g/mol = 18.02 g/mol

Now we can use the molar mass of water to determine the mass that corresponds to the given number of hydrogen atoms. Since there are two hydrogen atoms in one water molecule, we can calculate the mass of water using the formula:


Mass of water = (given number of hydrogen atoms / Avogadro's number) * molar mass of water

Substituting the values:
Mass of water = (6.54×10^24 / 6.022×10^23) * 18.02 g/mol = 90.9 g

Therefore, the correct answer is 97.9 g.

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