Middle School

How many grams of NaCl are needed to prepare 1.20 liters of a 2.00 M solution?

A) 70.2 g
B) 97.5 g
C) 117 g
D) 140 g

Answer :

The number of moles of the NaCl 1.20L of 2 M solution is 2.4. One mole is 58.5 g. Then the mass in grams of 2.4 moles is 140.4 grams. Thus, option D is correct.

The molarity of a solution is ratio of the number of moles in the solution to the volume of the solution in liters.

then,

number of moles = volume × molarity.

given,

molarity = 2 M

volume = 1.20 L.

number of moles = 2 M× 1.20 L = 2.4 moles.

mass of one mole of NaCl = 58.5 g

then mass of 2.4 moles = 140.4 grams

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Answer: D) 140g

Explanation: no. of moles of NaCl = molarity X volume in litres = 2 X 1.2 = 2.4, and molar mass or mass of 1 mole of NaCl = 58.44 g, so 2.4 moles NaCl = 140.256 g