Answer :
The amount in grams of NaCl that are contained in 350 mL of a 0.287 M solution of sodium chloride is B) 5.87 g.
To determine the grams of NaCl contained in 350 mL of a 0.287 M solution of sodium chloride, we can use the formula:
moles of solute = molarity × volume of solution (in liters)
First, we need to convert the volume of the solution from mL to liters:
350 mL × (1 L / 1000 mL) = 0.350 L
Next, we can calculate the moles of NaCl in the solution:
moles of NaCl = 0.287 M × 0.350 L = 0.10045 moles
Now, we'll convert moles of NaCl to grams using the molar mass of NaCl, which is approximately 58.44 g/mol:
grams of NaCl = 0.10045 moles × 58.44 g/mol ≈ 5.87 g
So, 5.87 grams of NaCl are contained in 350 mL of a 0.287 M solution of sodium chloride. The correct answer is option B) 5.87 g.
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