Answer :
Final answer:
A 35.5ml 4.58M solution of KOH, there are approximately 9.136 grams of KOH. This is calculated by converting the volume to liters, multiplying by the molarity to get moles of KOH, and then converting to grams using the molar mass of KOH.
Explanation:
The question is asking how many grams of KOH (potassium hydroxide) are present in a 35.5ml solution with a concentration of 4.58M (molar). The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. Hence, to find the amount of KOH in grams, we need to multiply the volume of the solution (in liters) by the molarity, then multiply that by the molar mass of KOH, which is approximately 56.11 g/mol.
To convert the volume from ml to L, we divide by 1000 (since there are 1000ml in 1L), hence 35.5ml = 0.0355L. Next, multiply the volume of the solution by the molarity: 0.0355L * 4.58M = 0.16279 moles of KOH. Finally, multiply this by the molar mass of KOH to find the mass in grams: 0.16279 moles * 56.11g/mol = 9.136g. So, there are approximately 9.136 grams of KOH in the solution.
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