Answer :
To find out how many grams of H₂O are present in 38.1 moles of H₂O, you can use the following method:
1. Understand the relationship between moles and grams:
- The molar mass of H₂O (water) is 18 grams per mole. This means that one mole of water weighs 18 grams.
2. Calculate the mass in grams:
- Multiply the number of moles by the molar mass to find the mass in grams.
- In this scenario, you have 38.1 moles of water.
3. Perform the calculation:
[tex]\[
\text{Mass of H₂O} = \text{Number of moles} \times \text{Molar mass of H₂O}
\][/tex]
[tex]\[
\text{Mass of H₂O} = 38.1 \times 18
\][/tex]
4. Get the result:
- When you multiply 38.1 by 18, you find that the mass of H₂O is 685.8 grams.
So, the number of grams of H₂O in 38.1 moles is approximately 685.8 grams.
1. Understand the relationship between moles and grams:
- The molar mass of H₂O (water) is 18 grams per mole. This means that one mole of water weighs 18 grams.
2. Calculate the mass in grams:
- Multiply the number of moles by the molar mass to find the mass in grams.
- In this scenario, you have 38.1 moles of water.
3. Perform the calculation:
[tex]\[
\text{Mass of H₂O} = \text{Number of moles} \times \text{Molar mass of H₂O}
\][/tex]
[tex]\[
\text{Mass of H₂O} = 38.1 \times 18
\][/tex]
4. Get the result:
- When you multiply 38.1 by 18, you find that the mass of H₂O is 685.8 grams.
So, the number of grams of H₂O in 38.1 moles is approximately 685.8 grams.