High School

How many days does it take for 16 g of palladium-103 to decay to 1.0 g?

The half-life of palladium-103 is 17 days.

Answer :

Final answer:

The half-life is the time it takes for half of a radioactive substance to decay. By using the formula N = log(initial_amount/final_amount) / log(2), it can be calculated that it would take approximately 68 days for 16g of palladium-103 to decay to 1g.

Explanation:

Palladium-103, like all radioactive substances, decays according to a concept known as half-life, which is the time it takes for half of a radioactive substance to decay. If the half-life of palladium-103 is 17 days, then after 17 days, half of the original quantity would remain.

To determine how many half-lives it takes for 16g to decay to 1g, you can use logarithms. The formula for calculating the number of half-lives is N = log(initial_amount/final_amount) / log(2). Inputting the values, N = log(16/1) / log(2) = 4 half-lives.

Since the half-life of palladium-103 is 17 days, we then multiply the half-life by the number of half-lives: 17 days/half-life x 4 half-lives = 68 days.

Therefore, it would take approximately 68 days for 16g of palladium-103 to decay to 1g.

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